$\left(8x+2y\right)^4$
$-\frac{1}{40}x+3=0$
$\frac{1}{secx}=secx\left(1-sin^2x\right)$
$-5a+2a$
$\frac{1-\cot^2\left(x\right)}{1+\cot^2\left(x\right)}=2\sin^2\left(x\right)-1$
$\int\left(sin\left(6\pi\right)\right)dx$
$29\:-\:\left(-53\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!