$\frac{675}{225}$
$2-x^3>0$
$\frac{1}{e^y}y'\:=\frac{x}{e^{x^2}}$
$30a^3x^2y-60a^2x^3y^2-90a^2xy$
$25^x=\left(\frac{1}{\:125}\right)^{3x-4}$
$\frac{2}{\sqrt{y}}$
$-5a-a$
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