$\left|-5+9\right|$
$sec^2x-secx\cdot cos^2x=tan^2x$
$\int w^5\left(w^6+23\right)^{10}dw$
$12a-6$
$\frac{x^2-2}{1-5x}$
$\frac{d}{dx}\sqrt{2}^{cosx}$
$-5+t=-15$
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