$\frac{dy}{dx}=\frac{5y}{2x}$

$m^5-2m^4+m^3=0$

$\sqrt{x+5}=4$

$\frac{dy}{dx}=\frac{\left(x-y\right)}{-x}$

$y:\frac{\left(\tan\theta+1\right)\left(\tan\theta+1\right)-\sec^2\theta}{\tan\theta}$

$\frac{15a-3}{24}$

$\lim_{h\to0}\left(\frac{e^{x+h}\cdot sin\left(x+h\right)-e^x\cdot sin\left(x\right)}{h}\right)$