$x^2+6x+9\le0$
$\lim_{x\to\infty}\left(\frac{x^2+1}{x^3-x}\right)$
$2y'+2y=0$
$\left(2x^2y^2\right)^2$
$-2x^2\frac{dy}{dx}-3xy=xy^2$
$\left(-5x-3y\right)\left(5x-3y\right)$
$\frac{dy}{dx}=5\left(y-8\right)$
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