$\sqrt[3]{\left(x+3\right)}^2$
$-3x^2+3x\cdot2x^2+3$
$\frac{dy}{dx}-2yx=1$
$0,07+0,2+0,08$
$\frac{dy}{dx}+\left(\frac{2\cdot y}{x}\right)=x^3$
$\sqrt{\frac{72x^5y^8}{2xy^4}}$
$a\left(x+1\right)+b\left(x+1\right)$
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