$\frac{1}{\cos\left(x\right)}\cdot\sin^2x$
$\cos\left(10\right)^2\sec\left(10\right)^2=1$
$\left(x-2\cdot y+z\right)^2$
$\left(64x^2-18y\right)$
$2x^2-2x-3$
$4\left(3x+\left(-4\right)\right)-9$
$\frac{2x^4-3x^2+6x-2}{x-3}$
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