$\lim_{x\to0}\left(x^2\cos\left(\frac{1}{x}\right)\right)$
$4\left(3s+1\right)+s$
$\lim_{x\to\infty}\left(\frac{ln\left(x\right)}{x+1}\right)$
$15a+-35b+82a-60b+-52$
$s6+12\ge9$
$\frac{28.48}{23.2}$
$\frac{2x^4-2x^3+4x^2-5}{x+2}$
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