$\int\frac{6}{\left(x+16\right)^3\:}dx$
$-x^2+4x-6=0$
$x^2+6x-78$
$\left(a^{x+1}-6\right)\left(2b^{x-1}-5\right)$
$-100x^2w^2z\left(25x^2w^2z\right)$
$\lim_{x\to3}\left(-x^3+13x^2-56x+81\right)$
$12x^3\cdot4x-8x$
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