$04\cdot04$
$\frac{\left(16x^2-8x\right)}{4x}$
$\log_b\left(2x\right)$
$x^2-6x+9=27$
$16x^2+16x+4$
$h\left(t\right)=\left(\frac{t^2}{t^3+t^2}\right)^2$
$4a+3-2y-5a-7+47$
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