$sinxcos2x$
$6\left(3x\right)^2-1$
$\frac{2+2\cos\left(x\right)}{\sin2\left(x\right)}=\frac{\tan\left(x\right)}{1-\cos\left(x\right)}$
$25x^2-10x-1$
$1=\frac{b+1}{3}$
$\frac{3x-8}{3x^2+5x-2}$
$-4x-20+2x-18$
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