$-2a\left(-b+3-2a\right)$
$\frac{2\tan x}{1+\tan^2x}=\sin x$
$\left(\frac{4x^3y^5}{3x^2y^3}\right)^4$
$9x^{4}+13x^{2}+5+\left(13-7x^{2}-9x^{4}\right)$
$\frac{dy}{dx}=\frac{y}{x\ln\left(y\right)}$
$\left(3\right)\left(-5\right)+v$
$\left(a^2-ab-b^2\right)^2$
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