$\lim_{x\to0}\left(\frac{1+\cos\left(3x\right)}{\left(x-\pi\right)^2}\right)$
$18x^3-120x^2-42x$
$\left(6\cdot16\right)+\left(3\cdot16\right)$
$\tan\left(2x\right)=\frac{4}{3}$
$\lim_{x\to infinito}\left(\frac{x\pi}{2}-x\arctan\left(x\right)\right)$
$+20+21-32+18-15+3-2-9$
$m^{-\frac{5}{4}}$
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