$3^{x^2+x-6}=1$

$1\frac{1}{2}\cdot24$

$\frac{\left(1-p\right)^2}{p}=0.01\:$

$6a-4=3a+5$

$\int\frac{x}{\sqrt[3]{\left(x^2+9\right)}}dx$

$\frac{x^2}{16}-\frac{3x}{16}+\frac{9}{4}$

$\lim_{x\to0}\left(\frac{\left(cos^2\left(x+\frac{\pi\:}{2}\right)\cdot\:\:\:cos\left(\frac{1}{x}\right)\right)}{x}\right)$