$\int7\left(3x-2\right)^2dx$
$\left|4+\left(-5\right)\right|-\left|3-\left(-8\right)\right|$
$\int\frac{x^2-4}{x^2\left(x+4\right)}dx$
$\left(\sqrt{x}+2x\right)^2$
$25x^2-5=-4$
$3\cdot.5$
$\frac{512}{16}$
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