$\frac{-9x^2+x^4+x-3}{x+3}$
$x^2=6x-5$
$x^2+11x-5=0$
$12ab^2+18a^2b^3-6a^3b^4$
$x^2-8x+14$
$x^8-\left(3yz\right)^4$
$2x\:+\:3\:+\:2\left(x\:+\:1\right)\:<\:-3\left(x\:-\:1\right)\:$
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