$\lim_{x\to\infty}\left(\frac{e^x}{6}\right)$
$\int_0^3\left(\frac{1}{x^{1.6}}\right)dx$
$\int\frac{x^2}{\left(2x-4\right)^5}dx$
$910+-12$
$\frac{\sin\left(t\right)}{1-\cos\left(t\right)}-\csc\left(t\right)$
$\frac{27}{64}g^6-h^{12}$
$15abx-9b^2x$
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