$\sqrt[2]{0.21}$
$x\left(2x+5\right)\left(2x-5\right)$
$b-5>-4$
$-\:4x^2\:+\:8\:=\:0$
$\frac{tan^2\left(\theta\right)}{tan^2\left(\theta\right)+1}$
$3t^2-30t+72$
$3\left(x+2\right)\left(x^2-2x+2\right)$
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