$\left(2x^2-x-3\right)\left(3x^2-3x-3\right)$
$25a^2b^3\cdot3ab$
$2x^2+4z^2$
$\left(4\right)^4\left(3\right)^2\left(\frac{1}{2}\right)^3$
$\frac{x^2-8x+15}{x-3}$
$\lim_{x\to\infty}\left(\frac{ln\left(5x^6\right)}{ln\left(4x^3\right)}\right)$
$\frac{x^4-3x^3-19x^2+4x+18}{x^2-3x-18}$
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