$\sqrt{x}-9.\sqrt{x}+9$
$\lim_{x\to\infty}\left(\frac{6e^x+10}{3e^x-5}\right)$
$x^2+4x\:-5$
$\int\frac{s^2}{\left(\sqrt{100+s^2}\right)^3}ds$
$-64x^2+36x^2$
$-3\left(1\right)^2+3\left(1\right)+2$
$-999\:-\:100\:$
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