$\int_0^1\:\frac{\sqrt{arctan\:x}}{1+x^2}dx$
$3x^2\cdot4x^3$
$-5\cdot16+-8-7-6\cdot7$
$\frac{dq}{dt\:}+\frac{q}{0.025}=2$
$\left(1+\sqrt{x}\right)^4$
$\frac{dy}{dx}=8-6x$
$2\cos\left(x\right)\sin\left(x\right)=\sqrt{3}\sin\left(x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!