$2888+42$
$\lim_{x\to\infty}\left(\frac{5x+4}{x^2-3}\right)$
$\left(x-3\right)^6=8$
$x^2+2y^2+z^2-4x-4y-2z+3=0$
$\left(12-\left(-17\right)+\left(-5\right)-19\right)-\left(57-10+19\right)$
$3x^5-7x^3+2x$
$24c-36+12$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!