$in\frac{xy^2}{e^3z^4}$
$6\:.\:-5\:.\:7$
$5x'+7x=0$
$\lim_{x\to-4}\left(\frac{4-\left|x\right|}{4+x}\right)$
$\left(2x+3-y-4z\right)\left(2x-3x+4z\right)$
$2x+3\le-9$
$\left(7y^3+2z^2\right)^2$
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