$32x^2y-50y$
$\int\:x^6\:ln\:x\:dx$
$\lim_{x\to0}\left(\frac{1-\cos\:\left(x\right)^2}{4x}\right)$
$4x^2-4x-16$
$y^2-4y-1=0$
$\frac{30m^{-2}}{5m^{-7}}\left(7m^{-8}\right)$
$16-40x^2+25x^4$
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