limx→0(x2+16x+55ln(3x+16))\lim_{x\to0}\left(\frac{x^2+16x+55}{ln\left(3x+16\right)}\right)x→0lim(ln(3x+16)x2+16x+55)
2x+164\frac{2x+16}{4}42x+16
(3x+2)⋅(x3−2x2+5x+1)\left(3x+2\right)\cdot\left(x^3-2x^2+5x+1\right)(3x+2)⋅(x3−2x2+5x+1)
5 ala 13 x 5 a la 175\:ala\:13\:x\:5\:a\:la\:175ala13x5ala17
p3−343q3p^3-343q^3p3−343q3
y3+3y2−2y3y^3+3y^2-2y^3y3+3y2−2y3
24(2)424\left(2\right)^424(2)4
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