$\int\frac{2x}{\left(x^2+3\right)^5}dx$
$\frac{d}{dx}2xy-11x^2y^2=0$
$-3\left(6x-8\right)+9=-18x+33$
$\frac{6x^2+19x+12}{x+2}$
$-12x^2\:+\:14xy\:-\:4y^2$
$\frac{d^2}{dx^2}\left(9x^2\ln\left(2x\right)\right)$
$\int x\cos^{-1}\left(10x^2\right)dx$
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