$4z^2+32z^2+16$
$x^2=\left(x-1\right)^2+\left(x-8\right)^2$
$x^2+5y-3xy+9y-x^2+9xy$
$\lim_{x\to0}\left(\frac{x^{2\:}-6x+12}{x-4}\right)$
$x^2-12x-16=0$
$104-\left(-92\right)$
$\int_{-8}^{\infty}\left(2\cdot\sin\left(x\right)\right)dx$
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