$\int\left(3x^2+6x-5\right)dx$
$\left(2x+1\right)\left(\frac{\left(2x+1\right)}{x-1}\right)$
$\tan\:\left(\theta\:\right)=-1.192$
$\int\frac{x^3}{\sqrt{4-x}}\:dx$
$s^2+6s+7$
$3y^2+6y$
$2\cdot2^6-3\cdot2^5-2^4+2^3-2^2+4\cdot2$
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