$2\left[6\left(2+n\right)+4\left(n+1\right)\right]$

$-6=6-q$

$\int\left(1-\cos\left(\frac{x}{2}\right)\right)^2\cdot\sin\left(\frac{x}{2}\right)dx$

$\frac{\left(-4\right)\left(-6\right)\left(-5\right)}{\left(+12\right)}$

$81-x^2y^2$

$\frac{1}{4}t-\frac{1}{2}=\frac{1}{8}t$

$3\log\:c-y\:\log$