$\left(a^3-2\right)\left(a^3-4\right)$
$3ydx=2xdy'$
$y'\:=\:3\sqrt[3]{y^2}$
$tanx+cosx=\frac{1}{sinx\cdot cosx}$
$\frac{7^5-k^5}{7-k}$
$-7^2.-7^5.-7^{-4}$
$\frac{dy}{dx}=015$
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