$\left(-2\right)\left(6\right)\left(7\right)$
$3\cdot4.95+2\cdot3.50$
$x^2+1\le4x-3$
$a^3-4x^3+5a^2x-3ax^2-x^3+ax^2-2a^2x$
$x\frac{dy}{dx}=\left(1+y^2\right)^{\frac{1}{2}}$
$\frac{8}{x-2}=\frac{5x-4}{x}$
$2sin3\theta\:=1$
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