$-\left(13+\left(-4\right)\right)-\left(-12\right)-2+4-\left(-1\right)$
$\left(a^3b^2-c^4\right)^3$
$\lim_{x\to1}\left(\frac{ln\:x}{x^2-x}\right)$
$\frac{x-8}{6}-\frac{x+5}{4}>13$
$\frac{54x^2-1}{3x^2-1}\:$
$\left(c-4\right)^5$
$2\left(a+2b\right)-a-2b$
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