$\frac{dy}{dx}=\frac{10x}{3y^3}$
$\cos\left(x\right)+\sin\left(x\right)=\cos\left(x\right)$
$\left(y\right)^'=\frac{-\left(x^2+y^2\right)}{2xy}$
$3x\:+\:2y\:=\:27$
$\frac{3x^{2}-6}{8-x}=x-2$
$2x+2y=10$
$\frac{60+80}{2}$
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