$\frac{x^3}{1+x^5}$
$\int_0^1\left(\frac{\left(x-4\right)}{\left(x^2-5x+6\right)}\right)dx$
$16:-5$
$\frac{dy}{dx}\left(4e^{x^3}\right)$
$3x^2y-15x$
$9c^2-40c+16$
$-\left(+4-6\right)+\left(-12+1\right)-5$
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