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f(x)=sin(2x)^2cos(2x)^2−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫π 6π 3(sin⁡2(2x)cos2(2x))dx\int_{\frac{\pi\:}{6}}^{\frac{\pi\:}{3}}\left(\sin^2\left(2x\right)cos^2\left(2x\right)\right)dx

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Final answer to the exercise

0.0654498−0.03125sin⁡(2π3)sin⁡(2π3)+0.03125sin⁡(4π3)sin⁡(4π3)+30.5128+−cos⁡(2π3)3sin⁡(2π3)80.0654498-0.03125\sin\left(\frac{2\pi }{3}\right)\sin\left(\frac{2\pi }{3}\right)+0.03125\sin\left(\frac{4\pi }{3}\right)\sin\left(\frac{4\pi }{3}\right)+\frac{3^{0.5}}{128}+\frac{- \cos\left(\frac{2\pi }{3}\right)^{3}\sin\left(\frac{2\pi }{3}\right)}{8}

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