$\:a+b=8$
$\sqrt[9]{x^{49}}$
$\left(4\:+\:x\right)y'\:=\:y^3$
$\sqrt{1-5x^2}y=x$
$-45-18+15-12-24$
$\tan\left(x\right)=\frac{\sin^3\left(x\right)}{\cos\left(x\right)-\cos^3\left(x\right)}$
$\frac{dy}{\:dt}-0,\:08y=300$
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