$\lim_{x\to-2}\left(\frac{4x^3+2}{5x+4}\right)$

$\frac{1-cos\left(x\right)}{1+cos\left(x\right)}=\frac{sec\left(x\right)-1}{sec\left(x\right)+1}$

$\lim_{x\to\infty}\left(\frac{\left(x^4ln^2cos\left(\frac{1}{x}\right)\right)}{x+1}\right)$

$\sqrt[3]{10^2+4\cdot29}$

$\frac{21a^3b}{14b^2a^3}$

$2\cdot3\cdot4:2\cdot5$

$12\:-\:\left[-8\:-\:\left(2\:-\:13\right)\right]\:$