$\lim_{x\to0}\left(\frac{\sin\left(2x\right)}{x^2\sin\left(x\right)}-\frac{2}{x^2}\right)$
$\frac{9x^3+3x^2+x-1\:}{3x\:-1\:}$
$4\left(1.75y-3.5\right)+1.25y$
$v^3\cdot2v$
$12b^2+3bd$
$\lim_{x\to-4}\left(x^2-3x\right)$
$\left(9y^3\right)\left(-8y^4\right)$
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