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∫cos7(x)sin(x)dx\int cos7\left(x\right)sin\left(x\right)dx
1

Simplify cos⁡(7x)sin⁡(x)\cos\left(7x\right)\sin\left(x\right) into sin⁡(8x)+sin⁡(−6x)2\frac{\sin\left(8x\right)+\sin\left(-6x\right)}{2} by applying trigonometric identities

∫sin⁡(8x)+sin⁡(−6x)2dx\int\frac{\sin\left(8x\right)+\sin\left(-6x\right)}{2}dx

Final answer to the exercise

∫sin⁡(8x)+sin⁡(−6x)2dx\int\frac{\sin\left(8x\right)+\sin\left(-6x\right)}{2}dx

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∫cos7(x)sin(x)dx
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