$\frac{d}{dx}x^{\:2}+3x\:+2y^2=6$
$4.24-3.01$
$\left(x^2y^{-1}\right)^2^{-3}$
$\left(2a+y\right)^5$
$\left(2x-3\right)\left(5x+8\right)=12$
$\left(x+y\right)ux+\left(x-y\right)uy=0$
$\int\left(\frac{1}{2x^2-16}\right)dx$
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