$$\frac{\sec\theta}{1+\sec\theta}=\frac{1-\cos\theta}{\sin^2\theta}$$

$$\sqrt{\frac{\sqrt[4]{a^2}\sqrt[3]{b^5}}{c^{-2}d}}$$

$$4^{\left(\frac{5}{3}\cdot\:\:3\right)}$$

$$x^6-3x$$

$$x^23x+9$$

$$18\left(.30+15-\left(-6\right)\right)$$

$$x^2-2>0$$