$\left(7+a^2b\right)^3$
$\frac{\log\left(2x-1\right)}{\log\left(4x-3\right)}=1$
$\left(x^{-2}x^4\right)^{-3}$
$\tan^2x-\frac{1}{3}=0$
$\frac{\frac{3}{2}a^6}{\frac{2}{5}a^4}$
$2cos\left(x^3\right)\cdot ln\left(7x\right)$
$\:xy-2x^2-y=3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!