$5 - \{ ( 8 - 6 : 3 ) + 4 ( 5 \cdot - 3 + 5 ) - 7 \}$
$\lim_{x\to1}\left(\frac{x-sinx}{x^3}\right)$
$n+0.9n\cdot0.5n$
$\left(x+2p\right)dp=0$
$\frac{18}{-3}\cdot\frac{-14}{7}$
$x\left(x-1\right)=25$
$x\:2\:+4x<=20$
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