$\frac{1}{\left(x+5\right)\left(x^2\right)}$
$\:sec^2\theta\:\:=\:1+\:tan^2\theta\:$
$3\left(-11\right)^4-3\left(-11\right)^3-\left(-11\right)^2+3\left(-1\right)-1\:$
$-27=-9y$
$\frac{\left(x^5\right)}{\left(4-x^2\right)}$
$\frac{-2x}{-2x}$
$m^2+18=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!