$-\frac{20}{3}n^2\cdot\frac{6}{4\:}n\:$
$-12-3-7+4-2+1+5$
$5\:a^{-2}\:b^1$
$\frac{-x^3+4x}{x^2-9}$
$\lim_{x\to\infty}\frac{x^2+6}{x^2+2x+5}$
$2x^{-2}$
$\left(\frac{3}{10}x+5\right)^2$
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