$3^{x+4}=-32$
$8x+1=-23$
$5x+2\le0$
$q\:+\:7p=\:z^3$
$\frac{2s^2+6}{s^4+5s^3+2s^2}$
$\int\left(-1+3x+5x^2\right)dx$
$\frac{16}{2\sqrt{8}}$
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