$\int\frac{5x-5}{\left(5x-3\right)^2}dx$

$\lim_{x\to\infty}\left(\left(2x+1\right)e^{-x}\right)$

$\left(-5.683\right)\cdot7$

$\int\left(x^2\left(7x^3+6\right)^6\right)dx$

$\left|6\left(8^2\right)-2\left(4^2\right)\right|$

$4x^2+5x-2=0$

$2u\left(3u-8\right)-3\left(3u-8\right)+\left(3u-8\right)$