$\ln\sqrt{x-2}=7$
$x=\frac{1}{3}x+26$
$\left(6\cdot m-9\cdot b\right)^2$
$\left(m-8\right)\left(m-9\right)$
$\lim_{x\to\infty}\left(\frac{x^5+x+4}{x^2+7}\right)$
$30=11-x$
$3.77\cdot0.25$
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