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x3+2x2−5x+7x+1\frac{x^3+2x^2-5x+7}{x+1}x+1x3+2x2−5x+7
1.1⋅1041.1\cdot10^41.1⋅104
−∫((3x2−5x)⋅sin(4x))dx-\int\left(\left(3x^2-5x\right)\cdot\sin\left(4x\right)\right)dx−∫((3x2−5x)⋅sin(4x))dx
7x2+21x−28= 07x^2+21x-28=\:07x2+21x−28=0
−21x27x5\frac{-21x^2}{7x^5}7x5−21x2
4y′(x)+2y′(x)y(x)=xy(x)24y'\left(x\right)+2y'\left(x\right)y\left(x\right)=xy\left(x\right)^24y′(x)+2y′(x)y(x)=xy(x)2
y=x2+6x+9y=x^2+6x+9y=x2+6x+9
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