$x^2-4x^2-21$
$49x^4-14x^2y+y^2$
$\int x^2\ln\left(x\right)du$
$\frac{4-x^2}{x+1}$
$\frac{-\frac{8t}{125}}{1+\frac{4}{125}\left(-t^2+16\right)^2}$
$\int\:te^{6t}dt$
$16x-192=0$
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